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3^(2x+3)-2.9^(x+1)=1/9
We move all terms to the left:
3^(2x+3)-2.9^(x+1)-(1/9)=0
We add all the numbers together, and all the variables
3^(2x+3)-2.9^(x+1)-(+1/9)=0
We get rid of parentheses
3^(2x+3)-2.9^(x+1)-1/9=0
We multiply all the terms by the denominator
(3^(2x+3))*9-(2.9^(x+1))*9-1=0
We move all terms containing x to the left, all other terms to the right
(3^(2x+3))*9-(2.9^(x+1))*9=1
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